How to determine the order of a reaction by the initial rates method?
How to determine the order of a reaction by the initial rates method?
A rate law is an expression which shows how the rate of a reaction depends on the concentrations of reactants. For the decomposition of NO2 we can write:
2NO2(g) → 2NO(g) + O2(g)
Rate = k [NO2]n (Rate Law)
k is the rate constant
and n is the order of reaction (n can be positive or negative, integer or fraction)
Both k and n must be determined experimentally.
For the general reaction:
aA + bB → cC + dD (1)
the rate law is given by: Rate = k. [A]m [B]n (2)
There are two types of rate laws:
- The differential rate law shows how the rate of a reaction depends on concentrations
- The integrated rate law shows how the concentrations of species in the reaction depend on time
The first step in understanding how a given chemical reaction occurs is to determine the form of the rate law. In this post we will show ways to obtain the differential rate law of a reaction.
The rate law - in its general form - for most reactions is given by equation 1. Therefore, the task of determining the rate law becomes one of determining the reaction order m and n.
In most cases the reaction orders are:
- Reaction order 0 in a reactant A (zero order reaction) ⇒ we write [A]0 ⇒changing the concentration of [A] the reaction rate R1 is not affected
- Reaction order 1 in a reactant A (first order reaction) ⇒ we write [A]1 ⇒changing the concentration of [A] the reaction rate R1 is affected proportionally (doubling [A] will double the rate R2 = 2* R1)
- Reaction order 2 in a reactant A (second order reaction) ⇒ we write [A]2 ⇒ doubling the concentration of [A] the reaction rate R1 is affected by a factor 22 (doubling [A] will affect the rate R2 = 4* R1) – tripling [A] the reaction rate R1 is affected by a factor 32 and becomes R3 = 9* R1)
N.B. Reaction rate depend on concentration but the rate constant k does not. The rate constant k is mainly affected by temperature and by the presence of a catalyst.
Example I.1
The initial rate of a chemical reaction A + B → C + D was measured for several different initial concentrations of A and B and the results are shown in Table I.1:
Experiment # | [A] (M) | [B] (M) | Initial Rate (M/s) |
1 | 0.100 | 0.100 | 2.0*10-5 |
2 | 0.100 | 0.200 | 2.0*10-5 |
3 | 0.200 | 0.100 | 8.0*10-5 |
Using the data in Table I.1 determine: a) the rate law for the reaction b) the rate constant
a) The general form of the rate law for the reaction given is the following:
R = Rate = k * [A]m * [B]n
We must determine the reaction orders m and n using the experimental data given in Table I.1.
By comparing experiments #1 and #2 we see that while the concentration of [A] remains constant the concentration of [B] is doubled but the reaction rate remains constant. Therefore, [B] does not affect the rate of reaction and that means n=0.
By comparing experiments #1 and #3 we see that while the concentration of [B] remains constant the concentration of [A] is doubled and the reaction rate increases fourfold. This indicates that the rate is proportional to [A]2.
From the above two observations the rate law for the reaction is given by the expression:
R = Rate = k * [A]2 * [B]0 = = k * [A]2 (3)
b) Using data from Experiment #1 (or from #2 or #3) and from equation (3):
k = R / [A]2 = 2.0*10-5 / (10-1)2 = 2.0*10-3 M-1s-1
Relevant Posts - Relevant Videos
Rate of a Chemical Reaction - Chemical Kinetics
Rates of Chemical Reactions and the Collision Model
References
- David W. Oxtoby, H.P. Gillis, Alan Campion, “Principles of Modern Chemistry”, Sixth Edition, Thomson Brooks/Cole, 2008
- Steven S. Zumdahl, “Chemical Principles” 6th Edition, Houghton Mifflin Company, 2009
- Ralph H. Petrucci, “General Chemistry”, 3rd Edition, Macmillan Publishing Co., 1982
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